150 câu trắc nghiệm Nguyên hàm - Tích phân cơ bản (P1)

$\int \sin 2xdx=-\frac{1}{2}\cos 2x+C$

$\int \sin 2xdx=\frac{1}{2}\cos 2x+C$

$\int \sin 2xdx=\cos 2x+C$

$\int \sin 2xdx=-\cos 2x+C$

${\int }_{}^{}f\left(x\right)dx=\frac{1}{3}\sin \left(3x+\frac{\mathrm{\pi }}{6}\right)+C$

${\int }_{}^{}f\left(x\right)dx=\sin \left(3x+\frac{\mathrm{\pi }}{6}\right)+C$

${\int }_{}^{}f\left(x\right)dx=-\frac{1}{3}\sin \left(3x+\frac{\mathrm{\pi }}{6}\right)+C$

${\int }_{}^{}f\left(x\right)dx=\frac{1}{6}\sin \left(3x+\frac{\mathrm{\pi }}{6}\right)+C$

$\int f\left(x\right)dx=2\tan \frac{x}{2}+C$

$\int f\left(x\right)dx=\tan \frac{x}{2}+C$

$\int f\left(x\right)dx=\frac{1}{2}\tan \frac{x}{2}+C$

$\int f\left(x\right)dx=-2\tan \frac{x}{2}+C$

$\int f\left(x\right)dx=-cot\left(x+\frac{\mathrm{\pi }}{3}\right)+C$

$\int f\left(x\right)dx=-\frac{1}{3}cot\left(x+\frac{\mathrm{\pi }}{3}\right)+C$

$\int f\left(x\right)dx=cot\left(x+\frac{\mathrm{\pi }}{3}\right)+C$

$\int f\left(x\right)dx=\frac{1}{3}cot\left(x+\frac{\mathrm{\pi }}{3}\right)+C$

$\int f\left(x\right)dx=\frac{{\sin }^{4}x}{4}+C$

$\int f\left(x\right)dx=-\frac{{\sin }^{4}x}{4}+C$

$\int f\left(x\right)dx=\frac{{\sin }^{2}x}{2}+C$

$\int f\left(x\right)dx=-\frac{{\sin }^{2}x}{2}+C$

$F\left(x\right)=-3e^x-x+C$

$F\left(x\right)=3e^x+e^x\ln e^x+C$

$F\left(x\right)=3e^x-\frac{1}{e^x}+C$

$F\left(x\right)=3e^x+x+C$

$\int f\left(x\right)dx={\left(\frac{2}{3}\right)}^x.\frac{1}{\ln 2-\ln 9}+C$

$\int f\left(x\right)dx={\left(\frac{9}{2}\right)}^x.\frac{1}{\ln 2-\ln 9}+C$

$\int f\left(x\right)dx={\left(\frac{2}{9}\right)}^x.\frac{1}{\ln 2-\ln 9}+C$

$\int f\left(x\right)dx={\left(\frac{2}{9}\right)}^x.\frac{1}{\ln 2+\ln 9}+C$

$\int f\left(x\right)dx=\frac{1}{4}{e}^{2x-1}+C$

$\int f\left(x\right)dx=e^{2x-1}+C$

$\int f\left(x\right)dx=\frac{1}{2}{e}^{2x-1}+C$

$\int f\left(x\right)dx=\frac{1}{2}\sqrt{e^{2x-1}}+C$

$\int f\left(x\right)dx=2\sqrt{2x-1}+C$

$\int f\left(x\right)dx=\sqrt{2x-1}+C$

$\int f\left(x\right)dx=\frac{\sqrt{2x-1}}{2}+C$

$\int f\left(x\right)dx=-2\sqrt{2x-1}+C$

$\int f\left(x\right)dx=2\sqrt{3-x}+C$

$\int f\left(x\right)dx=-\sqrt{3-x}+C$

$\int f\left(x\right)dx=-2\sqrt{3-x}+C$

$\int f\left(x\right)dx=-3\sqrt{3-x}+C$

$\int f\left(x\right)dx=\frac{1}{2}\sqrt{2x+1}+C$

$\int f\left(x\right)dx=\frac{2}{3}\left(2x+1\right)\sqrt{2x+1}+C$

$\int f\left(x\right)dx=-\frac{1}{3}\sqrt{2x+1}+C$

$\int f\left(x\right)dx=\frac{1}{3}\left(2x+1\right)\sqrt{2x+1}+C$

$\int f\left(x\right)dx=\frac{2}{9}\left(5-3x\right)\sqrt{5-3x}$

$\int f\left(x\right)dx=-\frac{2}{3}\left(5-3x\right)\sqrt{5-3x}$

$\int f\left(x\right)dx=-\frac{2}{9}\left(5-3x\right)\sqrt{5-3x}+C$

$\int f\left(x\right)dx=-\frac{2}{3}\sqrt{5-3x}+C$

$\int f\left(x\right)dx=-\frac{3}{4}\left(x-2\right)\sqrt[3]{x-2}+C$

$\int f\left(x\right)dx=\frac{3}{4}\left(x-2\right)\sqrt[3]{x-2}+C$

$\int f\left(x\right)dx=\frac{2}{3}\left(x-2\right)\sqrt[]{x-2}$

$\int f\left(x\right)dx=\frac{1}{3}{\left(x-2\right)}^{-\frac{2}{3}}+C$

$\int f\left(x\right)dx=-{(1-3x)}^{-\frac{2}{3}}+C$

$\int f\left(x\right)dx=-\frac{3}{4}(1-3x)\sqrt[3]{1-3x}+C$

$\int f\left(x\right)dx=\frac{1}{4}(1-3x)\sqrt[3]{1-3x}+C$

$\int f\left(x\right)dx=-\frac{1}{4}(1-3x)\sqrt[3]{1-3x}+C$

$x^2-3x+4\ln \left|x-1\right|+C$

$x^2+3x-4\ln \left|x-1\right|+C$

$x^2+3x+4\ln \left|x-1\right|+C$

$x^2-3x-4\ln \left|x-1\right|+C$

$\frac{x^3}{3}-\frac{x^2}{2}+x-2\ln \left|x+1\right|+C$

$\frac{x^3}{3}-\frac{x^2}{2}+2x-2\ln \left|x+1\right|+C$

$\frac{x^3}{3}-\frac{x^2}{2}+x+2\ln \left|x+1\right|+C$

$\frac{x^3}{3}+\frac{x^2}{2}+x-2\ln \left|x+1\right|+C$

$\frac{x^4}{4}-\frac{3x^2}{2}+2\ln \left|x\right|+\frac{1}{2x^2}+C$

$\frac{x^4}{4}-\frac{3x^2}{2}-3\ln \left|x\right|+\frac{1}{2x^2}+C$

$\frac{x^4}{4}+\frac{3x^2}{2}+2\ln \left|x\right|+\frac{1}{2x^2}+C$

$\frac{x^4}{4}-\frac{3x^2}{2}+3\ln \left|x\right|+\frac{1}{2x^2}+C$

$F\left(x\right)=x-\frac{2}{3}\sqrt{1-3x}+3$

$F\left(x\right)=x-\frac{2}{3}\sqrt{1-3x}-3$

$F\left(x\right)=x-\frac{2}{3}\sqrt{1-3x}+1$

$F\left(x\right)=4-\frac{2}{3}\sqrt{1-3x}$

2

3

-3

$\frac{1}{6}$

$F\left(x\right)=\frac{x^4}{4}-\frac{x^3}{3}+3x+2\ln \left|x\right|+C$

$F\left(x\right)=x^4-\frac{x^3}{3}+3x+\ln \left|x\right|+C$

$F\left(x\right)=3x^2-2x-\frac{1}{x^2}+C$

Đáp án khác

$\frac{1}{2}{e}^{2x}+4x+2e^{-2x}+C$

$\frac{1}{2}{e}^{2x}+4x-2e^{-2x}+C$

$e^{2x}+4x-2e^{-2x}+C$

$\frac{1}{2}{e}^{2x}-4x-2e^{-2x}+C$

$f\left(x\right)=\sin x-7\cos x+x$

$f\left(x\right)=-\sin x+7\cos x$

$f\left(x\right)=\sin x+7\cos x$

$f\left(x\right)=-\sin x-7\cos x$

$\tan x-cot2x+C$

$cot2x+C$

$\tan 2x-x+C$

$\tan x-cotx+C$

$\frac{x^5}{5}-x^3+x^2+2x+C$

$\frac{x^5}{5}+x^3+x^2+x+C$

$\frac{x^5}{5}-x^3+x^2-x+C$

$\frac{x^5}{5}-x^3+x^2+x+C$

$\ln \left|\frac{x+2}{x+1}\right|+C$

$\ln \left|\frac{x-1}{x-2}\right|+C$

$\ln \left|\frac{x+2}{x-1}\right|+C$

$\ln \left|\frac{x-2}{x-1}\right|+C$

$\tan x-x^2+e^x+C$

$cotx-x^2+e^x+C$

$\tan x-x^2-e^x+C$

$cotx-2x^2+e^x+C$

$\frac{x}{2}-\frac{\sin {\displaystyle x}}{2}$

$\frac{x}{2}+\frac{\sin {\displaystyle x}}{2}$

$x-\frac{\sin {\displaystyle x}}{2}+C$

$\frac{x}{2}-\frac{\sin {\displaystyle x}}{2}+C$

$x^2+x+3$

$x^2-x+2$

$x^2+2x+1$

Đáp án khác

$f\left(x\right)=2x+\frac{x^3}{3}+1$

$f\left(x\right)=x-\frac{x^3}{3}-2$

$f\left(x\right)=2x-\frac{x^3}{3}+1$

$f\left(x\right)=2x-\frac{x^3}{3}+2$

$f\left(x\right)=x^3-2\sqrt{x}-\frac{1}{x}-x$

$f\left(x\right)=x^3-\sqrt{x}-\frac{1}{x}-x$

$f\left(x\right)=x^3-2\sqrt{x}+\frac{1}{x}$

$f\left(x\right)=x^3-\frac{1}{2}\sqrt{x}-\frac{1}{x}-x$