Bộ 15 đề thi giữa kì 2 Toán 12 có đáp án năm 2022-2023 (Đề 5)

$y=x^3-3x^2+2$.

$y=\frac{x-1}{x+1}$.

$y=x^4+6x^2+3$.

$y=2x+1$.

2.

0.

3.

1.

$\left|\underset{0}{\overset{2}{\int }}\left(x^3-3x^2+x+1\right)\text{d}x\right|$.

$\underset{0}{\overset{2}{\int }}\left(x^3-3x^2+x+1\right)\text{d}x$.

$\underset{0}{\overset{2}{\int }}\left(x^3-3x^2-x+3\right)\text{d}x$.

$\underset{0}{\overset{2}{\int }}\left|x^3-3x^2+x+1\right|\text{d}x$.

$\underset{a}{\overset{b}{\int }}\left[f\left(x\right)+g\left(x\right)\right]\text{d}x=\underset{a}{\overset{b}{\int }}f\left(x\right)\text{d}x+\underset{a}{\overset{b}{\int }}g\left(x\right)\text{d}x$.

$\underset{a}{\overset{b}{\int }}\left[f\left(x\right)-g\left(x\right)\right]\text{d}x=\underset{a}{\overset{b}{\int }}f\left(x\right)\text{d}x-\underset{a}{\overset{b}{\int }}g\left(x\right)\text{d}x$.

$\underset{a}{\overset{b}{\int }}cf\left(x\right)\text{d}x=c\underset{a}{\overset{b}{\int }}f\left(x\right)\text{d}x$.

$\underset{a}{\overset{b}{\int }}f\left(x\right)\text{d}x=\underset{a}{\overset{c}{\int }}f\left(x\right)\text{d}x+\underset{c}{\overset{b}{\int }}f\left(x\right)\text{d}x$.

$\frac{4}{3}$.

$\frac{3}{4}$.

$4$.

$\frac{1}{3}$.

$18\pi$.

$12\pi$.

$4\pi$.

$6\pi$.

$M_1\left(0;2;0\right)$.

$M_2\left(-1;2;-3\right)$.

$M_3\left(1;0;3\right)$.

$M_4\left(0;0;3\right)$.

$\overrightarrow{n_1}=(1;-2;-3)$.

$\overrightarrow{n_2}=\left(1;-2;0\right)$.

$\overrightarrow{n_3}=\left(-1;2;0\right)$.

$\overrightarrow{n_4}=\left(2;-4;0\right)$.

3.

2.

1.

8.

$I\left(1;-3;0\right),R=\sqrt{14}$.

$I\left(-1;3;0\right),R=\sqrt{14}$.

$I\left(1;-3;0\right),R=\sqrt{10}$.

$I\left(-1;3;0\right),R=\sqrt{10}$.

$\underset{2}{\overset{1}{\int }}F\left(x\right)dx$.

$\underset{1}{\overset{2}{\int }}F\left(x\right)dx$.

$\underset{2}{\overset{1}{\int }}f\left(x\right)dx$.

$\underset{1}{\overset{2}{\int }}f\left(x\right)dx$.

$\frac{x}{5}+\frac{y}{-3}+\frac{z}{2}=1$.

$\frac{x}{-3}+\frac{y}{2}+\frac{z}{5}=1$.

$\frac{x}{2}+\frac{y}{5}+\frac{z}{-3}=1$.

$\frac{x}{2}+\frac{y}{-3}+\frac{z}{5}=1$.

$\frac{1}{2}{e}^{2x+3}+C$.

$\frac{2}{3}{e}^{2x+3}+C$.

$\frac{3}{2}{e}^{2x+3}+C$.

$\frac{1}{3}{e}^{2x+3}+C$.

${\left(x+1\right)}^2+{\left(y-4\right)}^2+{\left(z-1\right)}^2=12$.

${\left(x-1\right)}^2+{\left(y-2\right)}^2+{\left(z-3\right)}^2=12$.

$x^2+{\left(y-3\right)}^2+{\left(z-2\right)}^2=3$.

$x^2+{\left(y-3\right)}^2+{\left(z-2\right)}^2=12$.

3.

0.

2.

1.

3.

2.

0.

1.

$V=\frac{29}{30}$.

$V=\frac{1}{6}$.

$V=\frac{29}{30}\pi$.

$V=\frac{1}{6}\pi$.

2020.

2021.

2022.

2023.

$V=3a^3$.

$V=3a^3\sqrt{3}$.

$V=a^3\sqrt{3}$.

$V=a^3$

$\frac{x^5}{5}-\frac{x^3}{3}+C$.

$\frac{{\left(\sqrt{\ln x+1}\right)}^3}{5}-\frac{{\left(\sqrt{\ln x+1}\right)}^3}{3}+C$.

$-\frac{2{\left(\sqrt{\ln x+1}\right)}^5}{5}+\frac{2{\left(\sqrt{\ln x+1}\right)}^3}{3}+C$.

$\frac{2{\left(\sqrt{\ln x+1}\right)}^5}{5}-\frac{2{\left(\sqrt{\ln x+1}\right)}^3}{3}+C$

$6\pi a^2$.

$3\pi a^2$.

$8\pi a^2$.

$5\pi a^2$.

$m=2$

$m=1$

$m=3$

$m=-1$

$3x-2y+3z+2=0$.

$3x-2y+3z-2=0$.

$3x+2y+3z-2=0$.

$3x-2y-3z-2=0$.

$35°$.

$45°$.

$145°$.

$135°$.

$\pi \sqrt{3}$.

$\frac{\pi \sqrt{2}}{3}$.

$\frac{\pi \sqrt{3}}{2}$.

$\frac{\pi \sqrt{3}}{3}$.

$m<f\left(0\right)$.

$m\le f\left(0\right)$.

$m\le f\left(3\right)$.

$m<f\left(1\right)-\frac{2}{3}$.

2.

-1.

0.

1.

16,12.

16,9.

11,12.

12,16.

$\frac{1}{3}$.

$\frac{1}{4}$.

$\frac{1}{5}$.

$\frac{1}{10}$.

0.

-28.

30.

44.

$-x+2y+2z+5=0$.

$x-2y-9=0$.

$x-2y-2z+5=0$.

$x-2y+9=0$.

0.

$\frac{3}{4}$.

1.

2.

$\frac{\sqrt{3}-64}{15}$.

$\frac{33\sqrt{3}-64}{15}$.

$-\frac{\sqrt{3}}{5}$.

$-\frac{11\sqrt{3}}{5}$.

197.

196.

200.

201.

$\frac{1011}{2}$.

$\frac{1009}{2}$.

$\frac{2019}{2}$.

505.