Bài 45.1 trang 54 Sách bài tập Hóa học 9

2${\mathrm{CH}}_3$COOH + 2Na → ${\mathrm{CH}}_3$COONa + ${\mathrm{H}}_2$

2${\mathrm{CH}}_3$COOH + ${\mathrm{Na}}_2{\mathrm{CO}}_3$ → ${\mathrm{CH}}_3$COONa + ${\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

${\mathrm{CH}}_3$COOH + ${\mathrm{CaCO}}_3$ → ${\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2$Ca + ${\mathrm{H}}_2\mathrm{O}$ + ${\mathrm{CO}}_2$↑

2${\mathrm{CH}}_3$COOH + ${\mathrm{CaCO}}_3$ → ${\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2$Mg + ${\mathrm{H}}_2\mathrm{O}$ + ${\mathrm{CO}}_2$

${\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2$Ba + ${\mathrm{CuSO}}_4$ → ${\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2$Cu + ${\mathrm{BaSO}}_4$↓