700+ câu Trắc nghiệm Xử lý số liệu tín hiệu đáp án - Phần 9

$ZT{}_1\left[x\left(n-2\right)\right]=Z{}^{-2}\cdot X{}^1\left(Z\right)$

$\text{Z}\text{T}{}_1\left[\text{x}\left(\text{n}-2\right)\right]=\text{Z}{}^{-2}\cdot \text{X}{}^1\left(\text{Z}\right)+\text{x}\left(-1\right)+\text{x}\left(-2\right)$

$\text{Z}\text{T}{}_1\left[\text{x}\left(\text{n}-2\right)\right]=Z{}^{-2}X{}^1\left(Z\right)+x\left(-2\right)+Z{}^{-1}x\left(-1\right)$

$\text{Z}\text{T}{}_1\left[\text{x}\left(\text{n}-2\right)\right]=\text{X}{}^1\left(\text{Z}\right)+\text{x}\left(-1\right)+\text{x}\left(-2\right)$

$H\left(Z\right)=2+2Z{}^{-1}+Z{}^{-2}$

$H\left(Z\right)=2+2Z{}^1+Z{}^2$

$H\left(Z\right)=1+2Z{}^1+2Z{}^2$

$H\left(Z\right)=1+2Z{}^{-1}+Z{}^{-2}$

$x\left(n\right)=\frac{1}{2j\pi }\oint X\left(Z\right)\cdot Z{}^{-n}dZ$

$x\left(n\right)={\displaystyle \sum }_{n=-\infty }\mathrm{Unsupported\; }x\left(Z\right)Z{}^{-n}$

$\text{I}\text{Z}\text{T}\left[x\left(Z\right)\right]=\frac{1}{2j\pi }\oint {}_{c}x\left(Z\right)\cdot Z{}^{n-1}dZ$

$x\left(n\right)={\displaystyle \sum }_{n=-\infty }\mathrm{Unsupported\; }x\left(Z\right)Z{}^{n-1}$

$H\left(Z\right)={\sum }_{r=0}^M\frac{b{}_{r}Z{}^{-r}}{a{}_0}$

$H\left(Z\right)={\sum }_{r=0}^{M}b{}_{r}Z{}^{-r}$

$H\left(Z\right)=\frac{{\sum }_{r=0}^{M}b{}_{r}Z{}^{-r}}{{\sum }_{k=0}^{N}a{}_{k}Z{}^{-k}}$

$H\left(Z\right)=\frac{{\sum }_{r=1}^{M}b{}_{r}Z{}^{-r}}{{\sum }_{k=1}^Na{}_{k}Z{}^{-k}}$

$X\left(Z\right)=\sum {}_{n=\infty }x\left(n\right)Z{}^{-n}$

$X\left(Z\right)=\sum {}_{n=N}^{N}x\left(n\right)Z{}^{-2n,\pi }$

$X\left(Z\right)=\sum {}_{n=N}^{N}x\left(n\right)Z{}^{-n}$

$X\left(Z\right)=\sum {}_{n=-x}^{\infty }x\left(n\right)Z{}^{-2nz}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1+0.8Z}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-0.8Z{}^{-1}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1+0.8Z{}^{-1}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-0.8Z}$

$X\left(Z\right)=1+Z{}^{-1}+Z$

$X\left(Z\right)=1+Z{}^{-1}+Z{}^{-2}$

$X\left(Z\right)=1+Z{}^{-1}$

$X\left(Z\right)=Z{}^{-1}+Z$

$X\left(Z\right)=Z{}^2+2\cdot Z{}^1+1$

$X\left(Z\right)=Z{}^{-2}+2\cdot Z{}^{-1}+1$

$X\left(Z\right)=Z{}^2+Z+1$

$X\left(Z\right)=Z{}^{-2}+Z{}^{-1}+1$

Bậc của đa thức $\text{K}\left(\text{Z}\right)$ nhỏ hơn hoặc bằng bậc của đa thức $\text{C}\left(\text{Z}\right)$

Bậc của đa thức $K\left(Z\right)$ nhỏ hơn bậc của đa thức $C\left(Z\right)$

Bậc của đa thức $K\left(Z\right)$ bằng bậc của đa thức $C\left(Z\right)$

Bậc của đa thức $K\left(Z\right)$ lớn hơn hoặc bằng bậc của đa thức $C\left(Z\right)$

$\delta \left(n+4\right)$

$\text{u}\left(\text{n}\right)$

$u\left(n+3\right)$

$x\left(n\right)=\left\{0,\underset{\_}{2},2,-1,0\right\}$

$X\left(Z\right)=2Z{}^{-2}Z\ne 0$

$X\left(Z\right)=2Z{}^{-2}Z\ne \infty$

$X\left(Z\right)=2Z{}^{2}Z\ne 0$

$X\left(Z\right)=3+4Z{}^1$

$X\left(Z\right)=3+4Z{}^{-1}Z\ne \infty$

$X\left(Z\right)=3+4Z{}^{-1}$

$X\left(Z\right)=2Z{}^2+3+4Z{}^{-1}Z\ne 0,Z\ne \infty$

$X\left(Z\right)=3+4Z{}^{-1}Z\ne 0$

$X\left(Z\right)=2Z{}^{-2}+3+4Z{}^{-1}Z\ne 0,Z\ne \infty$

$X\left(Z\right)=3+4Z{}^{-1}+2Z{}^2$

$X{}^{+}\left(Z\right)=3+Z{}^{-1}Z\ne 0$

$X\left(Z\right)=Z{}^1+3+4Z{}^{-1}Z\ne 0$

$X\left(Z\right)=Z{}^{-2}+1+1Z{}^{-1}Z\ne 0$

$X\left(Z\right)=3+Z{}^{-1}+2Z{}^2$

$X{}^{+}\left(Z\right)=3+Z{}^{-4}Z\ne 0$

$X+\left(Z\right)=3Z\ne 0$

$X\left(Z\right)=4Z{}^4+3Z\ne 0$

$X\left(Z\right)=4Z{}^{-4}-3$

$\frac{1}{1-2Z{}^{-1}}$ ROC. $\left|Z\right|>2$

$\frac{-1}{1+2Z{}^{-1}}$ ROC. $\left|Z\right|>2$

$\frac{-1}{1-2Z{}^{-1}}$ ROC. $\left|Z\right|>2$

$\frac{1}{1+2Z{}^{-1}}$ ROC. $\left|Z\right|>2$

$\text{Z}{}_0=0,\text{Z}{}_{\text{p}}=0.8$

$\text{Z}{}_0=0.8,\text{Z}{}_{\text{p}}=0$

$Z{}_0=0,Z{}_p=-0.8$

$\text{Z}{}_0=-0.8,\text{Z}{}_{\text{p}}=0$

$\text{Z}{}_{01}=0,\text{Z}{}_{02}=0.25;\text{Z}{}_{\text{p}1}=1.5,\text{Z}{}_{\text{p}2}=-0.5$

$\text{Z}{}_{01}=0,\text{Z}{}_{02}=-0.25;\text{Z}{}_{\text{p}1}=1.5,\text{Z}{}_{\text{p}2}=-0.5$

$\text{Z}{}_{01}=0,\text{Z}{}_{02}=-0.25;\text{Z}{}_{\text{p}1}=-1.5,\text{Z}{}_{\text{p}2}=0.5$

$\text{Z}{}_{01}=0,\text{Z}{}_{02}=0.25;\text{Z}{}_{\text{p}1}=-1.5,\text{Z}{}_{\text{p}2}=0.5$

$\text{Z}{}_{01}=1;\text{Z}{}_{\text{p}1}=0,\text{Z}{}_{\text{p}2}=2$

$\text{Z}{}_{01}=0,;\text{Z}{}_{\text{p}1}=2,\text{Z}{}_{\text{p}2}=1$

$Z{}_{01}=1;Z{}_{p1}=0,Z{}_{p2}=-2$

$\text{Z}{}_{01}=0;\text{Z}{}_{\text{p}1}=-2,\text{Z}{}_{\text{p}2}=0$

$H\left(Z\right)=\sum _{n=-\infty }h\left(n\right)Z{}^{-n}$

$H\left(Z\right)=\sum _{n=0}h\left(n\right)Z{}^n$

$H\left(Z\right)=\sum _{n=0}h\left(n\right)Z{}^{-n}$

$H\left(Z\right)=\sum _{n=\infty }h\left(n\right)Z{}^n$

$H\left(Z\right)=\sum _{n=-\infty }h\left(n\right)Z{}^{-n}$

$H\left(Z\right)=\sum _{n=0}h\left(n\right)Z{}^n$

$H\left(Z\right)=\sum _{n=0}h\left(n\right)Z{}^{-n}$

$H\left(Z\right)=\sum _{n=n}h\left(n\right)Z{}^n$

$H\left(Z\right)=1-2Z{}^{-2}+4Z{}^{-4}$

$H\left(Z\right)=1-2Z{}^2+4Z{}^4$

$H\left(Z\right)=2Z{}^{-2}+4Z{}^{-4}$

$H\left(Z\right)=1+2Z{}^{-2}+4Z{}^{-4}$

$\text{u}\left(\text{n}\right)$

$-\text{u}\left(\text{n}\right)$

$u\left(-n-1\right)$

$-\text{u}\left(-\text{n}-1\right)$

$(0.5){}^{\text{n}}\text{u}\left(\text{n}\right)$

$(0.5){}^{\text{n}-1}\text{u}\left(\text{n}-1\right)$

$(0.5){}^{\text{n}}\text{u}\left(\text{n}-1\right)$

$(0.5){}^{\text{n}-1}\text{u}\left(\text{n}\right)$

$\text{y}\left(\text{n}\right)=\left\{\underset{\_}{0},0,6,2,4,0\right\}$

$y\left(n\right)=\left\{\underset{\_}{0},0,4,6,2,0\right\}$

$y\left(n\right)=\left\{\underset{\_}{0},1,2,6,4,0\right\}$

$y\left(n\right)=\left\{\underset{\_}{0},0,2,6,4,0\right\}$