700+ câu Trắc nghiệm Xử lý số liệu tín hiệu đáp án - Phần 10

$x\left(n\right)=b\cdot 3{}^n\cdot u\left(-n-1\right)-a{}^n\cdot u\left(n\right)$

$x\left(n\right)=a{}^n\cdot u\left(n\right)-b\cdot 3{}^n\cdot u\left(-n-1\right)$

$x\left(n\right)=a{}^n\cdot u\left(n\right)+b\cdot 3{}^n\cdot u\left(-n-1\right)$

$x\left(n\right)=b\cdot 3{}^n\cdot u\left(n\right)+a{}^n\cdot u\left(n\right)$

$X\left(Z\right)=\frac{2}{(Z-1){}^2}+\frac{1}{Z-1}+\frac{1}{Z+1}$

$\text{X}\left(\text{Z}\right)=\frac{1}{(Z-1){}^2}-\frac{1}{Z-1}-\frac{1}{Z+1}$

$\text{X}\left(\text{Z}\right)=\frac{3}{(Z-1){}^2}+\frac{0,5}{Z-1}-\frac{0,5}{Z+1}$

$\text{X}\left(\text{Z}\right)=\frac{1}{(Z-1){}^2}-\frac{2}{Z-1}-\frac{1}{Z+1}$

$x\left(n\right)=3{}^n\cdot u\left(n\right)-2{}^n\cdot u\left(n\right)$

$\text{x}\left(\text{n}\right)=3{}^{\text{n}}\cdot \text{u}\left(\text{n}\right)-2{}^{\text{n}-1}\cdot \text{u}\left(\text{n}-1\right)$

$x\left(n\right)=3{}^{n-1}\cdot u\left(n-1\right)+2{}^n\cdot u\left(n\right)$

$\text{x}\left(\text{n}\right)=3{}^{\text{n}-1}\cdot \text{u}\left(\text{n}-1\right)-2{}^{\text{n}-1}\cdot \text{u}\left(\text{n}-1\right)$

$\text{h}\left(\text{n}\right)=2\delta \left(\text{n}\right)+\delta \left(\text{n}-1\right)+2\delta \left(\text{n}-2\right)$

$\text{h}\left(\text{n}\right)=2\delta \left(\text{n}\right)+2\delta \left(\text{n}-1\right)+\delta \left(\text{n}-2\right)$

$\text{h}\left(\text{n}\right)=2\delta \left(\text{n}\right)+2\delta \left(\text{n}-1\right)+2\delta \left(\text{n}-2\right)$

$\text{h}\left(\text{n}\right)=2\delta \left(\text{n}\right)+3\delta \left(\text{n}-1\right)+\delta \left(\text{n}-2\right)$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-2Z{}^{-1}-3Z{}^{-2}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-2Z{}^{-1}+3Z{}^{-2}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1+2Z{}^{-1}+3Z{}^{-2}}$

$H\left(Z\right)=\frac{1-Z{}^{-1}}{1-2Z{}^{-1}+3Z{}^{-2}}$

$X\left(Z\right)=1+Z{}^{-1}+Z$

$X\left(Z\right)=1+Z{}^{-1}+Z{}^{-2}$

$X\left(Z\right)=1+Z{}^{-1}$

$X\left(Z\right)=Z{}^{-1}+Z$

$X\left(Z\right)=Z{}^2+2\cdot Z{}^1+1$

$X\left(Z\right)=Z{}^{-2}+2\cdot Z{}^{-1}+1$

$X\left(Z\right)=Z{}^2+Z+1$

$X\left(Z\right)=1$

$u\left(n\right)$

$-\text{u}\left(\text{n}\right)$

$u\left(-n-1\right)$

$-u\left(-n-1\right)$

$(0.5){}^{\text{n}}\text{u}\left(\text{n}\right)$

$(0.5){}^{\text{n}-1}\text{u}\left(\text{n}-1\right)$

$(0.5){}^{\text{n}}\text{u}\left(\text{n}-1\right)$

$(0.5){}^{\text{n}-1}\text{u}\left(\text{n}\right)$

Miền hội tụ $\left|z\right|>1$

Miền hội tụ với mọi Z

Miền hội tụ $\left|z\right|<1$

Không tồn tại biến đổi Z

$\text{X}\left(\text{Z}\right)=\frac{1}{1-3z{}^{-1}}$ với $\left|z\right|>3$

$\text{X}\left(\text{Z}\right)=\frac{z}{3}+\frac{1}{1-3z{}^{-1}}$ vói $\frac{1}{3}>\left|z\right|>3$

$\text{X}\left(\text{Z}\right)=\frac{z}{3}+\frac{1}{1-3z{}^{-1}}$ với $\left|z\right|>3$

$\text{X}\left(\text{Z}\right)=\frac{1}{1-3z{}^{-1}}$ vói $\frac{1}{3}>\left|z\right|>3$

$Z{}_{01}=2,Z{}_{02}=3,Z{}_{p1}=0,Z{}_{p2}=1$

$\text{Z}{}_{01}=2,\text{Z}{}_{02}=3,\text{Z}{}_{\text{p}2}=1$

$Z{}_{01}=2,Z{}_{02}=3,Z{}_{\text{p}1}=0$

$\text{Z}{}_{01}=2,\text{Z}{}_{\text{p}1}=0,\text{Z}{}_{\text{p}2}=1$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-2Z{}^{-1}-3Z{}^{-2}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1-2Z{}^{-1}+3Z{}^{-2}}$

$H\left(Z\right)=\frac{1+Z{}^{-1}}{1+2Z{}^{-1}+3Z{}^{-2}}$

$H\left(Z\right)=\frac{1-Z{}^{-1}}{1-2Z{}^{-1}+3Z{}^{-2}}$

$H\left(Z\right)=\frac{1}{1-4Z{}^{-2}}$

$H\left(Z\right)=\frac{Z{}^{-1}}{1+4Z{}^{-2}}$

$H\left(Z\right)=\frac{Z{}^{-1}}{1-4Z{}^{-2}}$

$H\left(Z\right)=\frac{1}{1+4Z{}^{-2}}$