DẠNG 1. KHÁI NIỆM NGUYÊN HÀM, TÍNH CHẤT CỦA NGUYÊN HÀM
36 câu hỏi
\({f^\prime }(x) = F(x)\forall x \in \mathbb{R}.\)
\({{\rm{f}}^\prime }({\rm{x}}) = {\rm{F}}({\rm{x}}) + {\rm{C}}({\rm{C}} \in \mathbb{R})\forall {\rm{x}} \in \mathbb{R}\)
\({F^\prime }(x) = f(x)\forall x \in \mathbb{R}.\)
\({F^\prime }(x) = f(x) + C(C \in \mathbb{R}\backslash \{ 0\} )\forall x \in \mathbb{R}.\)
Chọn đáp án C
\(\int f (x)dx = {f^\prime }(x) + C.\)
\(\int {{f^\prime }} (x)dx = f(x).\)
\(\int f (x)dx = {f^\prime }(x).\)
\(\int {{f^\prime }} (x)dx = f(x) + C.\)
Chọn đáp án D
\(\int {(f(} x) + g(x))dx = \int f (x)dx + \int g (x)dx\) với \(f(x),g(x)\) là hai hàm bất kì liên tục trên \(\mathbb{R}.\)
\(\int {({\rm{f}}(} {\rm{x}}) \cdot {\rm{g}}({\rm{x}})){\rm{dx}} = \int {\rm{f}} ({\rm{x}}){\rm{dx}} \cdot \int {\rm{g}} ({\rm{x}}){\rm{dx}}\) với \({\rm{f}}({\rm{x}}),{\rm{g}}({\rm{x}})\) là hai hàm bất kì liên tục trên \(\mathbb{R}.\)
\(\int {(f(} x) + g(x))dx = \int f (x)dx - \int g (x)dx\) với \(f(x),g(x)\) là hai hàm bất kì liên tục trên \(\mathbb{R}.\)
\(\int {\frac{{{\rm{f}}({\rm{x}})}}{{{\rm{g}}({\rm{x}})}}} {\rm{dx}} = \frac{{\int {\rm{f}} ({\rm{x}}){\rm{dx}}}}{{\int {\rm{g}} ({\rm{x}}){\rm{dx}}}}\) với \({\rm{f}}({\rm{x}}),{\rm{g}}({\rm{x}})\) là hai hàm bất kì liên tục trên \(\mathbb{R}.\)
Chọn đáp án A
\(\int {{\pi ^3}} {\rm{dx}} = \frac{{{\pi ^4}}}{4} + C.\)
\(\int {{\pi ^3}} {\rm{dx}} = 3{\pi ^2} + \) C.
\(\int {{\pi ^3}} {\rm{dx}} = 3{\pi ^2}.\)
\(\int {{\pi ^3}} dx = {\pi ^3}x + C.\)
Chọn đáp án D
\(\int 0 {\rm{dx}} = - {\rm{x}} + C.\)
\(\int 0 {\rm{dx}} = {\rm{x}} + C.\)
\(\int 0 {\rm{dx}} = {\rm{Cx}},{\rm{C}} \in \mathbb{R}\backslash \{ 0\} .\)
\(\int 0 {\rm{dx}} = {\rm{C}}.\)
Chọn đáp án D
\(\int k dx = x + C.\)
\(\int {{\rm{kdx}}} = {\rm{kx}} + {\rm{C}}.\)
\(\int k dx = C.\)
\(\int {{\rm{kdx}}} = {\rm{kx}}.\)C.
Chọn đáp án B
\({\rm{y}} = {{\rm{x}}^{\alpha + 1}}.\)
\(y = (\alpha + 1){x^{\alpha + 1}}.\)
\({\rm{y}} = \frac{{{{\rm{x}}^\alpha }}}{{\alpha + 1}}.\)
\(y = \frac{{{x^{\alpha + 1}}}}{{\alpha + 1}}.\)
Chọn đáp án D
\(\int {\sin } xdx = - \sin x + C.\)
\(\int {\sin } xdx = \sin x + C.\)
\(\int {\sin } xdx = - \cos x + C.\)
\(\int {\sin } xdx = \cos x + C.\)
Chọn đáp án C
\(\int {\cos } xdx = - \sin x + C.\)
\(\int {\cos } xdx = \sin x + C.\)
\(\int {\cos } xdx = - \cos x + C.\)
\(\int {\cos } xdx = \cos x + C.\)
Chọn đáp án B
\(\int {\frac{1}{{{{\sin }^2}x}}} dx = - \cot x + C.\)
\(\int {\frac{1}{{{{\sin }^2}x}}} dx = - \tan x + C.\)
\(\int {\frac{1}{{{{\sin }^2}x}}} dx = \cot x + C.\)
\(\int {\frac{1}{{{{\sin }^2}x}}} dx = \tan x + C.\)
Chọn đáp án A
\(\int {\frac{1}{{{{\cos }^2}x}}} dx = - \cot x + C.\)
\(\int {\frac{1}{{{{\cos }^2}x}}} dx = - \tan x + C.\)
\(\int {\frac{1}{{{{\cos }^2}x}}} dx = \cot x + C.\)
\(\int {\frac{1}{{{{\cos }^2}x}}} dx = \tan x + C.\)
Chọn đáp án D
\(\int {{{\rm{e}}^{\rm{x}}}} {\rm{dx}} = {{\rm{e}}^{ - {\rm{x}}}} + C.\)
\(\int {{{\rm{e}}^{\rm{x}}}} dx = {{\rm{e}}^{\rm{x}}} + C.\)
\(\int {{{\rm{e}}^{\rm{x}}}} {\rm{dx}} = - {{\rm{e}}^{\rm{x}}} + C.\)
\(\int {{{\rm{e}}^{\rm{x}}}} {\rm{dx}} = - {{\rm{e}}^{ - {\rm{x}}}} + C.\)
Chọn đáp án B
\(\int {{{\rm{a}}^{\rm{x}}}} {\rm{dx}} = \frac{{{{\rm{a}}^{\rm{x}}}}}{{\ln {\rm{a}}}} + C.\)
\(\int {{a^{\rm{x}}}} dx = {{\rm{a}}^{\rm{x}}}\ln {\rm{a}} + C.\)
\(\int {{{\rm{a}}^{\rm{x}}}} {\rm{dx}} = \frac{{{{\rm{e}}^{\rm{x}}}}}{{\ln {\rm{a}}}} + \) C.
\(\int {{{\rm{a}}^{\rm{x}}}} {\rm{dx}} = {{\rm{e}}^{\rm{x}}}\ln {\rm{a}} + C.\)
Chọn đáp án A
\(\int {\frac{1}{{\rm{x}}}} {\rm{dx}} = |{\rm{x}}| + {\rm{C}}.\)
\(\int {\frac{1}{{\rm{x}}}} {\rm{dx}} = \ln |{\rm{x}}| + {\rm{C}}.\)
\(\int {\ln } xdx = x + C.\)
\(\int {\ln } |x|dx = \ln x + C.\)
Chọn đáp án B
\({\rm{y}} = {{\rm{a}}^{\rm{x}}}.\)
\({\rm{y}} = {{\rm{a}}^{{\rm{x}} + 1}}.\)
\(y = \frac{{{a^x}}}{{\ln a}}.\)
\({\rm{y}} = {{\rm{a}}^{\rm{x}}}\ln {\rm{a}}.\)
Chọn đáp án C
\({\rm{y}} = \frac{1}{{{\rm{x}}\ln {\rm{e}}}}.\)
\(y = \frac{1}{{x\ln a}}.\)
\(y = \frac{1}{x}.\)
\(y = \frac{{\ln {\rm{a}}}}{{\rm{x}}}.\)
Chọn đáp án B
\({\rm{y}} = {\rm{a}}\cos ({\rm{ax}} + {\rm{b}}).\)
\({\rm{y}} = \frac{{ - \cos ({\rm{ax}} + {\rm{b}})}}{{\rm{a}}}\)
\({\rm{y}} = - {\rm{a}}\cos ({\rm{ax}} + {\rm{b}}).\)
\({\rm{y}} = \frac{{\cos ({\rm{ax}} + {\rm{b}})}}{{\rm{a}}}.\)
Chọn đáp án A
\(y = - a\sin (ax + b).\)
\({\rm{y}} = \frac{{ - \sin ({\rm{ax}} + {\rm{b}})}}{{\rm{a}}}.\)
\({\rm{y}} = {\rm{a}}\sin ({\rm{ax}} + {\rm{b}}).\)
\({\rm{y}} = \frac{{\sin ({\rm{ax}} + {\rm{b}})}}{{\rm{a}}}.\)
Chọn đáp án A
\({\rm{y}} = \frac{1}{{{\rm{ax}} + {\rm{b}}}}.\)
\(y = \frac{{ - 1}}{{{\rm{ax}} + {\rm{b}}}}.\)
\(y = \frac{{ - {\rm{a}}}}{{{\rm{ax}} + {\rm{b}}}}.\)
\({\rm{y}} = \frac{{\rm{a}}}{{{\rm{ax}} + {\rm{b}}}}.\)
Chọn đáp án D
\({\rm{y}} = - {{\rm{e}}^{{\rm{ax}} + {\rm{b}}}}.\)
\({\rm{y}} = {{\rm{e}}^{{\rm{ax}} + {\rm{b}}}}.\)
\(y = a{e^{ax + b}}.\)
\(y = \frac{{{e^{ax + b}}}}{a}\)
Chọn đáp án C
25.
625.
5.
125.
Chọn đáp án B
\(f(x) = \sin x.\)
\(f(x) = - \cos x.\)
\(f(x) = - \sin x.\)
\(f(x) = \cos x.\)
Chọn đáp án D
\(y = \cos 2x.\)
\({\rm{y}} = \frac{{\cos 2{\rm{x}}}}{2}.\)
\(y = 2\cos 2x.\)
\(y = \frac{{ - \cos 2x}}{2}.\)
Chọn đáp án C
\(y = \cos 2x.\)
\({\rm{y}} = \frac{{\cos 2{\rm{x}}}}{2}.\)
\(y = 2\cos 2x.\)
\(y = \frac{{ - \cos 2x}}{2}.\)
Chọn đáp án D
\({\rm{y}} = {{\rm{x}}^6}.\)
\({\rm{y}} = 5{{\rm{x}}^4}.\)
\({\rm{y}} = \frac{{{{\rm{x}}^6}}}{6}.\)
\({\rm{y}} = 6{{\rm{x}}^5}.\)
Chọn đáp án C
\({\rm{y}} = \frac{{{{\rm{x}}^4}}}{4} + 1\)
\(y = \frac{{{x^4}}}{4} + 2\)
\({\rm{y}} = \frac{{{{\rm{x}}^4}}}{4} + 3.\)
\({\rm{y}} = 3{{\rm{x}}^2}.\)
Chọn đáp án D
\(\frac{{{x^2}}}{2} - x - \ln |x| + C\)
\(\frac{{{x^2}}}{2} - x + \ln |x| + C.\)
\(\frac{{{x^2}}}{2} + x - \ln |x| + C.\)
\({x^2} - x - \ln |x| + C.\)
Chọn đáp án A
\(\int {\frac{{{\rm{dx}}}}{{{{\rm{x}}^3}}}} = \frac{1}{{{{\rm{x}}^2}}} + C.\)
\(\int {\frac{{dx}}{{{x^3}}}} = \frac{2}{{{x^2}}} + C.\)
\(\int {\frac{{dx}}{{{x^3}}}} = \frac{{ - 1}}{{2{x^2}}} + C.\)
\(\int {\frac{{dx}}{{{x^3}}}} = \frac{{ - 2}}{{{x^2}}} + C.\)
Chọn đáp án C
\(\int {\frac{{{\rm{dx}}}}{{\sqrt {{{\rm{x}}^3}} }}} = \frac{1}{{\sqrt {\rm{x}} }} + C.\)
\(\int {\frac{{{\rm{dx}}}}{{\sqrt {{{\rm{x}}^3}} }}} = \frac{2}{{3\sqrt {\rm{x}} }} + \) C.
\(\int {\frac{{dx}}{{\sqrt {{{\rm{x}}^3}} }}} = \frac{{ - 2}}{{\sqrt {\rm{x}} }} + C.\)
\(\int {\frac{{{\rm{dx}}}}{{\sqrt {{{\rm{x}}^3}} }}} = \frac{2}{{\sqrt {\rm{x}} }} + C.\)
Chọn đáp án C
\( - \cos x + x + C.\)
\( - \cos x - x + C.\)
\(\cos x + x + C.\)
\(\cos x - x + C.\)
Chọn đáp án A
\(\frac{{x + \sin x}}{2} + C.\)
\(\frac{{x - \sin x}}{2} + C.\)
\(\frac{{x - \cos x}}{2} + C.\)
\(\frac{{x + \cos x}}{2} + C.\)
\(\int {{{\sin }^2}} \frac{x}{2}dx = \int {\frac{{1 - \cos x}}{2}} dx = \frac{1}{2}\int {(1 - \cos x)} dx = \frac{{x - \sin x}}{2} + \) C. Chọn B.
\(\frac{{x + \sin x}}{2} + C.\)
\(\frac{{x - \sin x}}{2} + C.\)
\(\frac{{x - \cos x}}{2} + C.\)
\(\frac{{x + \cos x}}{2} + C.\)
\(\int {{{\cos }^2}} \frac{x}{2}dx = \int {\frac{{1 + \cos x}}{2}} dx = \frac{1}{2}\int {(1 + \cos x)} dx = \frac{{x + \sin x}}{2} + \) C. Chọn A.
\({\rm{y}} = \frac{{{{\tan }^3}{\rm{x}}}}{3}.\)
\(y = \tan x - x.\)
\(y = - \tan x + x.\)
\(y = \tan x.\)
\(\int {{{\tan }^2}} xdx = \int {\left[ {\left( {1 + {{\tan }^2}x} \right) - 1} \right]} dx = \int {\left( {\frac{1}{{{{\cos }^2}x}} - 1} \right)} dx = \tan x - x + C.\) Chọn B.
\({\rm{y}} = \frac{{{{\cot }^3}{\rm{x}}}}{3}.\)
\(y = \cot x - x.\)
\(y = \cot x.\)
\(y = - \cot x - x.\)
\(\int {{{\cot }^2}} xdx = \int {\left[ {\left( {1 + {{\cot }^2}x} \right) - 1} \right]} dx = \int {\left( {\frac{1}{{{{\sin }^2}x}} - 1} \right)} dx = - \cot x - x + C.\)
Chọn D.
\( - \frac{1}{{25}} \cdot \frac{{{{(0,4)}^{\rm{x}}}}}{{\ln 0,4}} + \frac{3}{{25}} \cdot \frac{{{{(0,6)}^{\rm{x}}}}}{{\ln 0,6}} + C.\)
\(\frac{1}{{25}} \cdot \frac{{{{(0,4)}^{\rm{x}}}}}{{\ln 0,4}} + \frac{3}{{25}} \cdot \frac{{{{(0,6)}^{\rm{x}}}}}{{\ln 0,6}} + C.\)
\( - \frac{1}{{25}} \cdot \frac{{{{(0,4)}^{\rm{x}}}}}{{\ln 0,4}} - \frac{3}{{25}} \cdot \frac{{{{(0,6)}^{\rm{x}}}}}{{\ln 0,6}} + C.\)
\(\frac{1}{{25}} \cdot \frac{{{{(0,4)}^{\rm{x}}}}}{{\ln 0,4}} - \frac{3}{{25}} \cdot \frac{{{{(0,6)}^{\rm{x}}}}}{{\ln 0,6}} + C.\)
\(\int {\frac{{{2^x} - {3^{x + 1}}}}{{{5^{x + 2}}}}} dx = \frac{1}{{25}}\int {{{\left( {\frac{2}{5}} \right)}^x}} dx - \frac{3}{{25}}\int {{{\left( {\frac{3}{5}} \right)}^x}} dx = \frac{1}{{25}} \cdot \frac{{{{(0,4)}^x}}}{{\ln 0,4}} - \frac{3}{{25}} \cdot \frac{{{{(0,6)}^x}}}{{\ln 0,6}} + C.\)
Chọn D.
\(\int {{e^{ax + b}}} dx = {e^b}\int {{{\left( {{e^a}} \right)}^x}} dx = {e^b} \cdot \frac{{{{\left( {{e^a}} \right)}^x}}}{{\ln {e^a}}} + C = \frac{{{e^{ax + b}}}}{a} + C.\)
\(\int {{e^{ax + b}}} dx = {e^b}\int {{{\left( {{e^a}} \right)}^x}} dx = {e^b} \cdot {\left( {{e^a}} \right)^x} + C = {e^{ax + b}} + C.\)
\(\int {{e^{ax + b}}} dx = {e^b}\int {{{\left( {{e^a}} \right)}^x}} dx = {e^b} \cdot \frac{{{{\left( {{e^a}} \right)}^x}}}{{\ln {e^a}}} + C = \frac{{{e^{bx + a}}}}{a} + C.\)
\(\int {{e^{ax + b}}} dx = {e^b}\int {{{\left( {{e^a}} \right)}^x}} dx = {e^b} \cdot \frac{{{{\left( {{e^a}} \right)}^x}}}{{\ln {{\rm{e}}^a}}} + C = \frac{{{e^{ax + b}}}}{b} + C.\)
Chọn đáp án A






