Đề kiểm tra 15 phút Toán 12 Chương 3 Giải tích có đáp án (Đề 1)

A. $\ln x-\ln x^2+C$

B. $\ln x-\frac{1}{x}+C$

C. $\ln x+\frac{1}{x}+C$

D. $\ln \left|x\right|-\frac{1}{x}+C$

A. ${\int }_{}^{}\frac{dx}{x}=\ln x +\hspace{0.17em}C$

B. ${\int }_{}^{}{x}^{\alpha }dx=\frac{x^{\alpha +1}}{\alpha +1} +\hspace{0.17em}C\left(\alpha \ne -1\right)$

C. ${\int }_{}^{}{\alpha }^{x}dx=\frac{{\alpha }^x}{\ln \alpha } +\hspace{0.17em}C\left(0<\alpha \ne -1\right)$

D.  ${\int }_{}^{}\frac{1}{{\cos }^{2}x}dx=\tan x+C$

A. $F\left(x\right)=\frac{2x^3}{3}-\frac{3}{x}+C$

B. $F\left(x\right)=\frac{x^3}{3}-\frac{3}{x}+C$

C. $F\left(x\right)=-3x^3-\frac{3}{x}+C$

D. $F\left(x\right)=\frac{2x^3}{3}+\frac{3}{x}+C$

A. $F\left(x\right)=2x-\frac{3}{x}+2$

B. $F\left(x\right)=2\ln \left|x\right|+\frac{3}{x}+2$

C. $F\left(x\right)=2x+\frac{3}{x}-4$

D. $F\left(x\right)=2\ln \left|x\right|-\frac{3}{x}+4$

A. $F\left(x\right)=\frac{3x^2}{2}-\frac{3}{2x}-\frac{1}{2}$

B. $F\left(x\right)=\frac{3x^2}{4}-\frac{3}{2x}-\frac{7}{4}$

C. $F\left(x\right)=\frac{3x^2}{2}+\frac{3}{4x}-\frac{7}{4}$

D. $F\left(x\right)=\frac{3x^2}{4}+\frac{3}{2x}+\frac{7}{4}$

A. $F\left(x\right)=\frac{x^3}{3}-\frac{1}{x}+2x+C$

B. $F\left(x\right)=\frac{x^3}{3}+\frac{1}{x}+2x+C$

C. $F\left(x\right)=\frac{\frac{x^3}{3}+x}{{\displaystyle \frac{x^2}{2}}}+C$

D. $F\left(x\right)={\left(\frac{\frac{x^3}{3}+x}{{\displaystyle \frac{x^2}{2}}}\right)}^2+C$

A. $y=f\left(x\right)=\frac{x^4}{4}-\frac{x^2}{2}-3$

B. $y=f\left(x\right)=\frac{x^4}{4}-\frac{x^2}{2}+3$

C. $y=f\left(x\right)=\frac{x^4}{4}+\frac{x^2}{2}+3$

D. $y=f\left(x\right)=3x^2-1$

A. $-\frac{1}{6}\sin 6x+\frac{1}{4}\sin 4x+C$

B. $6\sin 6x-5\sin 4x+C$

C. $\frac{1}{6}\sin 6x-\frac{1}{4}\sin 4x+C$

D. $-6\sin 6x+\sin 4x+C$

A. $e^{3x}$

B. 3$e^{3x}$

C. $\frac{1}{3}{e}^{3x}$

D. -3$e^{3x}$