Bài tập Phân tích đa thức thành nhân tử bằng phương pháp nhóm hạng tử (có lời giải chi tiết)

A. $\left(5x-2y\right)\left(x+4y\right)$

B. $\left(5x^2+4\right)\left(x-2y\right)$

C. $\left(x+2y\right)\left(5x-4\right)$

D. $\left(5x-4\right)\left(x-2y\right)$

A. $\left(x+2a\right)\left(x-1\right)$

B. $\left(x-2a\right)\left(x+1\right)$

C. $(x+2a)\left(x+1\right)$

D. $\left(x-2a\right)\left(x-1\right)$

A. $\left(a^2 + b\right)\left(5x – 2y\right)$

B. $\left(a^2 – b\right)\left(2x – 5y\right)$

C. $\left(a^2 + b\right)\left(2x + 5y\right)$

D. $\left(a^2 + b\right)\left(2x – 5y\right)$

A. $\left(x+1\right)$

B. $\left(x+a\right)$

C. $\left(x+2\right)$

D. $\left(x-1\right)$

A. $\left(x + y + 2xy\right)$

B. $\left(x – y + 2xy\right)$

C. $\left(x – y + xy\right)$

D. $\left(x – y + 3xy\right)$

A. $x^3 – 4x^2 – 9x + 36 = \left(x + 3\right)\left(x-2\right)\left(x+2\right)$

B. $x^3 – 4x^2 – 9x + 36 = \left(x-3\right)\left(x+3\right)\left(x-4\right)$

C. $x^3 – 4x^2 – 9x + 36 = \left(x-9\right)\left(x-2\right)\left(x+2\right)$

D. $x^3 – 4x^2 – 9x + 36 = \left(x+3\right)\left(x-3\right)\left(x-2\right)$

A. $2a^2{c}^2 – 2abc + bd – acd = \left(2ac-d\right)\left(ac-b\right)$

B. $2a^2{c}^2 – 2abc + bd – acd = \left(2ac-d\right)\left(ac+b\right)$

C. $2a^2{c}^2 – 2abc + bd – acd = \left(2ac+d\right)\left(ac-b\right)$

D. $2a^2{c}^2 – 2abc + bd – acd = \left(2ac+d\right)\left(ac+d\right)$

A. ax – bx + ab – $x^2$ = $\left(x+b\right)\left(a-x\right)$

B. $x^2$ – $y^2$ + 4x + 4 = $\left(x+y\right)\left(x-y+4\right)$

C. ax + ay – 3x – 3y = $\left(a-3\right)\left(x+y\right)$

D. xy + 1 – x – y = $\left(x-1\right)\left(y-1\right)$

A. m = 8; n = 9

B. m = 9; n = 8

C. m = -8; n = 9

D. m = 8; n = -9

A. m = 5; n = -1

B. m = -5; n = -1

C. m = 5; n = 1

D. m = -5; n = 1

A. m < 0

B. 1 < m < 3

C. 2 < m < 4

D. m $>$ 4

A. m < 0

B. 1 < m < 3 

C. 2 < m < 4

D. m > 4

A. x = 2; x = -2

B. x = 0; x = 2

C. x = 0; x = -2

D. x = -2

A. $x=\frac{7}{2}$  hoặc x = -2

B. $x=-\frac{7}{2}$  hoặc x = 2

C. $x=\frac{7}{2}$  hoặc x = 2

D. $x=-\frac{7}{2}$  hoặc x = -2

A. 1   

B. 2

C. 0   

D. 3

A. 1

B. 2

C. 0

D. 3

A. A > 1

B. A > 0

C. A < 0

D. A ≥ 1

A. N > 1200

B. N < 1000

C. N < 0

D. N > 1000

A. b – a

B. a – b

C. a + b

D. -a – b 

A. 700

B. 620

C. 640

D. 670

A. 130

B. 120

C. 140

D. 150

A. A = 20

B. A = 40

C. A = 16 

D. A = 28

A. 36 

B. 42  

C. 48 

D. 56

A. a = b = c  

B. a + b + c = 1

C.a = b = c hoặc a + b + c = 0 

D. a = b = c hoặc a + b + c = 1

A. ${(a + c + b)}^2(a + b{)}^2$

B. ${(a + c)}^2{(a + b)}^2(b +c)$

C. ${(a + c)}^2 + {(a + b)}^2 + {(b + c)}^2$

D. ${(a + c)}^2{(a + b)}^2{(b + c)}^2$

A. $x{(x + 1)}^4 + x{(x + 1)}^3 + x{(x + 1)}^2 + {(x + 1)}^2 = {(x + 1)}^5$

B. $x{(x + 1)}^4 + x{(x + 1)}^3 + x{(x + 1)}^2 + {(x + 1)}^2 = {(x + 1)}^6$

C.$x{(x + 1)}^4 + x{(x + 1)}^3 + x{(x + 1)}^2 + {(x + 1)}^2 = {(x + 1)}^4\left(x-1\right)$

D. $x{(x + 1)}^4 + x{(x + 1)}^3 + x{(x + 1)}^2 + {(x + 1)}^2 = {(x + 1)}^4\left(x+2\right)$