15 câu Trắc nghiệm Toán 8 Cánh diều Bài 4: Vận dụng hằng đẳng thức vào phân tích đa thức thành nhân tử có đáp án

A. 1000³ + 1

B. 1000³ – 1

C. 1000³

D. 1001³

A. 1200

B. 800

C. 1500

D. 1800

A. $\left(\text{x}-\text{y}-\text{3}\right)\left(\text{x}-\text{y + 3}\right)$

B. $\left(\text{x}-\text{y}-\text{9}\right)\left(\text{x}-\text{y + 9}\right)$

C. $\left(\text{x}+\text{y}-\text{3}\right)\left(\text{x}+\text{y + 3}\right)$

D. $\left(\text{x}+\text{y}-9\right)\left(\text{x}+\text{y }-\text{ 9}\right)$

A. 1

B. – 1

C. 2

D. 4

A. 2

B. 1

C. 0

D. 4

A. $\left(b+c+a\right)\left(b+c-a\right)\left(a+b-c\right)\left(a-b+c\right)$

B. $\left(b+c+a\right)\left(b-c-a\right)\left(a+b-c\right)\left(a-b+c\right)$

C. $\left(b+c+a\right)\left(b+c-a\right){\left(a+b-c\right)}^2$

D. $\left(b+c+a\right)\left(b+c-a\right)\left(a+b-c\right)\left(a-b-c\right)$

A. 8900

B. 9000

C. 9050

D. 9100

A. 7.

B. 8.

C. 9.

D. 10.

A. x = 1

B. x = – 1

C. x = 2

D. x = 5

A. A > 1

B. A > 0

C. A < 0

D. $A\ge 1$

A. ${\left(x+y\right)}^2\left(x^2-xy+y^2\right)\left(x^2+xy+y^2\right)$

B. ${\left(x+y\right)}^2\left(x^2-xy+y^2\right)\left(x^2+xy+y^2\right)$

C. ${\left(x+y\right)}^2\left(x^2-xy+y^2\right)\left(x^2+xy+y^2\right)$

D. ${\left(x+y\right)}^2\left(x^2+2xy+y^2\right)\left(y-x\right)\left(x^2+xy+y^2\right)$

A. B < 8300

B. B > 8500

C. B < 0

D. B > 8300

A. ${\text{x}}^2-6\text{x}+9={\left(\text{x}-3\right)}^2$

B. $\frac{{\text{x}}^2}{4}+2\text{xy}+4{\text{y}}^2={\left(\frac{\text{x}}{4}+2\text{y}\right)}^2$

C. $\frac{{\text{x}}^2}{4}+2\text{xy}+4{\text{y}}^2={\left(\frac{\text{x}}{2}+2\text{y}\right)}^2$

D. $4{\text{x}}^2-4\text{xy}+{\text{y}}^2={(2\text{x}-\text{y})}^2$

A. a = b = c

D. a = b = c hoặc a + b + c = 1

C. a = b = c hoặc a + b + c = 0

D. a = b = c hoặc a + b + c = 1