12 câu Trắc nghiệm Toán 10 Kết nối tri thức Nhị thức Newton (Thông hiểu) có đáp án

16x⁴ − 32x³ + 24x² − 8x + 1;

16x⁴ + 32x³ + 24x² + 8x + 1;

16x⁴ − 32x³ + 24x² + 8x + 1;

16x⁴ + 32x³ + 24x² − 8x + 1.

x⁵ + 5x⁴ −10x³ + 10x² − 5x + 1;

x⁵ + 10x⁴ + 40x³ + 80x² + 80x + 8;

x⁵ + 5x⁴ + 10x³ + 10x² + 5x + 1;

x⁵ − 5x⁴ + 10x³ − 10x² + 5x − 1.

$1-\frac{4}{x}-\frac{6}{x^2}-\frac{4}{x^3}-\frac{1}{x^4}$

$1+\frac{4}{x}+\frac{6}{x^2}+\frac{4}{x^3}+\frac{1}{x^4}$

$-1+\frac{4}{x}-\frac{6}{x^2}+\frac{4}{x^3}-\frac{1}{x^4}$

$1-\frac{4}{x}+\frac{6}{x^2}-\frac{4}{x^3}+\frac{1}{x^4}$

15;

234;

243;

729.

14 + 13$\sqrt{2}$;

15 + 12$\sqrt{2}$;

17 + 12$\sqrt{2}$;

17 + 5$\sqrt{2}$.

1,1254;

1,0254;

1,254;

1,1524.

32;

8;

4;

16.

0;

1;

2;

3.

k ∈ (14; 24);

k ∈ (28; 38);

k ∈ (32; 42);

k ∈ (44; 54).

252;

352;

452;

425.

$z^8+4z^6+6z^4+4z^2+12z^3+10z^2+12z+13+\frac{8}{z}+\frac{6}{z^2}+\frac{4}{z^3}+\frac{1}{z^4}$

$z^8+4z^6+6z^4+4z^2+12z^3+10z^2+12z+13+\frac{8}{z}+\frac{6}{z^2}+\frac{4}{z^3}-\frac{1}{z^4}$

$z^8+4z^6+6z^4+4z^2+12z^3+10z^2+12z-13+\frac{8}{z}+\frac{6}{z^2}+\frac{4}{z^3}+\frac{1}{z^4}$

$z^8+4z^6+6z^4+4z^2+12z^3+10z^2+2z+13+\frac{8}{z}+\frac{6}{z^2}+\frac{4}{z^3}+\frac{1}{z^4}$