5 câu Trắc nghiệm Phương sai và độ lệch chuẩn có đáp án (Nhận biết)

$\overline{x}=\frac{n_1{x}_1+n_2{x}_2+\mathrm{...}+n_k{x}_k}{n^2}$

$\overline{x}=\frac{n_1{x}_1+n_2{x}_2+\mathrm{...}+n_k{x}_k}{n}$

$\overline{x}=n_1{x}_1+n_2{x}_2+\mathrm{...}+n_k{x}_k$

$\overline{x}=n\left(n_1{x}_1+n_2{x}_2+\mathrm{...}+n_k{x}_k\right)$

$S_X^2=\frac{1}{n}\left[n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2\right]$

$S_X^2=\frac{1}{n}\left[{\left(x_1-\overline{x}\right)}^2+{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+{\left(x_k-\overline{x}\right)}^2\right]$

$S_X^2={\left(x_1-\overline{x}\right)}^2+{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+{\left(x_k-\overline{x}\right)}^2$

$S_X^2=\frac{1}{n^2}\left[n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2\right]$

$\sqrt{S_X^2}$

$S_X^2$

$S_X^4$

$\sqrt{S_X}$

$S_X^2=\frac{1}{n^2}\left[n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2\right]$

$S_X=\frac{1}{n}\left[n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2\right]$

$S_X=\sqrt{\frac{1}{n}\left[n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2\right]}$

$S_X^2=\frac{1}{n}\sqrt{n_1{\left(x_1-\overline{x}\right)}^2+n_2{\left(x_2-\overline{x}\right)}^2+\mathrm{...}+n_k{\left(x_k-\overline{x}\right)}^2}$

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