Xét phản ứng phân hủy N2O5 theo phương trình hóa học: 2N2O5(g)->4NO2(g) + O2(g), xảy ra ở 56 ℃ cho kết quả theo bảng:Thời gian (s)N2O5 (M)NO2 (M)O2 (M)2400,03880,03150,

$\overline{v}=-\frac{1}{2}.\frac{\Delta C_{N_2{O}_5}}{\Delta t}\text{=}\frac{1}{4}.\frac{\Delta C_{N{O}_2}}{\Delta t}\text{=}\frac{1}{1}.\frac{\Delta C_{O_2}}{\Delta t}$

$\overline{v}=-\frac{1}{2}.\frac{(0,0388-0,0196)}{360}\text{=}\frac{1}{4}.\frac{(0,0699-0,0315)}{360}\text{=}\frac{1}{2}.\frac{(0,0175-0,0079)}{360}\text{=}\text{2}\text{,}\text{6}\text{7}\text{.}\text{1}{\text{0}}^{-5}\text{(}\text{M}\text{/}\text{s}\text{)}$