Ứng với công thức phân tử C4H11N có bao nhiêu đồng phân amine bậc 1?

Đáp án: 4

Có 4 đồng phân amine bậc I là:

$\text{C}\text{H}{}_3-\text{C}\text{H}{}_2-\text{C}\text{H}{}_2-\text{C}\text{H}{}_2-\text{N}\text{H}{}_2$ (butan-1-amine)

$\text{C}\text{H}{}_3-\text{C}\text{H}{}_2-\text{C}\text{H}\left(\text{N}\text{H}{}_2\right)-\text{C}\text{H}{}_3$ (butan-2-amine)

$\left(\text{C}\text{H}{}_3\right){}_2\text{C}\text{H}-\text{C}\text{H}{}_2-\text{N}\text{H}{}_2$ (2-methylpropan-1-amine)

$\left(\text{C}\text{H}{}_3\right){}_3\text{C}-\text{N}\text{H}{}_2$ (2-methylpropan-2-amine)