Tính tổng sau Sn=(2+1/2)^2+(4+1/4)^2+....+(2^n+1/2^n)^2
Giải thích
Chọn D
Sn=22+122+2+24+124+2+...+22n+122n+2 =22+24+...+22n+122+124+...+122n+2n =4.1−4n1−4+141−14n1−14+2n= 43. ( 4n-1)+ 13.4n-14n+ 2n =4n−134−14n+2n.
Chọn D
Sn=22+122+2+24+124+2+...+22n+122n+2 =22+24+...+22n+122+124+...+122n+2n =4.1−4n1−4+141−14n1−14+2n= 43. ( 4n-1)+ 13.4n-14n+ 2n =4n−134−14n+2n.