Tính tổng \(S = {2024^4} - 8088
Giải thích
\(S = {2024^4} - 8088 \cdot {2024^3} + 6 \cdot {\left( {2024 \cdot 2022} \right)^2} - 8096 \cdot {2022^3} + {2022^4}\)
\( = {2024^4} - 4 \cdot {2024^3} \cdot 2022 + 6 \cdot {\left( {2024 \cdot 2022} \right)^2} - 4 \cdot 2024 \cdot {2022^3} + {2022^4}\)
\( = {\left( {2024 - 2022} \right)^4} = {2^4} = 16\).