tính tổng S = 2018C1009 + 2018C1010 + 2018C1011 +...+ 2018C2018
Giải thích
Đáp án B
Ta có 1+x2018=∑k=02018C2018kxk=C20180+C20181x+...+C20182018x2018.
Chọn x=1⇒22018=C20180+C20181+...+C20182018.
Vì Cnk=Cnn−k⇒22018=2C20181010+C20181011+C20182018+C20181009=2S+C20181009⇒S=22017+12C20181009.