Tính tổng A biết: A = 1 + 1 /3 + 1/ 6 + 1 /10 + 1 /15 + 1/ 21 + 1/ 28 + 1 /36 + 1/ 45 + . . . . . .

Ta có:

\(\frac{1}{2} \times A = \frac{1}{2}(1 + \frac{1}{3} + \frac{1}{6} + \frac{1}{{10}} + \frac{1}{{15}} + \frac{1}{{21}} + \frac{1}{{28}} + \frac{1}{{36}} + \frac{1}{{45}})\)

\( = \frac{1}{2} + \frac{1}{6} + \frac{1}{{12}} + \frac{1}{{20}} + \frac{1}{{30}} + \frac{1}{{42}} + \frac{1}{{56}} + \frac{1}{{72}} + \frac{1}{{90}}\)

\( = \frac{9}{{10}}\)

Suy ra: \(A = \frac{9}{{10}}:\frac{1}{2} = \frac{9}{{10}} \times \frac{2}{1} = \frac{9}{5}\)

Đáp Số: \(A = \frac{9}{5}\)