Tính tổng : 1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+2007)(x+2008)
Giải thích
1x(x+1)+1x+1(x+2)+1x+2(x+3)+........+1x+2007(x+2008)
=1x−1x+1+1x+1−1x+2+1x+2−1x+3+.........+1x+2007−1x+2008
=1x−1x+2008=2008x(x+2008)
1x(x+1)+1x+1(x+2)+1x+2(x+3)+........+1x+2007(x+2008)
=1x−1x+1+1x+1−1x+2+1x+2−1x+3+.........+1x+2007−1x+2008
=1x−1x+2008=2008x(x+2008)