Tính tích phân sau: sin 3x . cos x dx
Giải thích
Chọn C
∫0π2sin3x cosxdx=12∫0π2sin4x+sin2xdx=12∫0π2sin4xdx+∫0π2sin2xdx=12-14cos4x-12cos2xπ20=12-14cos2π-12cosπ--14cos0-12cos0=12-14+12+14+12=12
Chọn C
∫0π2sin3x cosxdx=12∫0π2sin4x+sin2xdx=12∫0π2sin4xdx+∫0π2sin2xdx=12-14cos4x-12cos2xπ20=12-14cos2π-12cosπ--14cos0-12cos0=12-14+12+14+12=12