Tính tích phân sau:  |2x-3 | dx

\[\int\limits_0^2 {\left| {2x - 3} \right|\,} {\rm{d}}x = \int\limits_0^{\frac{3}{2}} {\left( {3 - 2x} \right)} \,{\rm{d}}x + \int\limits_{\frac{3}{2}}^2 {\left( {2x - 3} \right)} \,{\rm{d}}x = \left. {\left( {3x - {x^2}} \right)} \right|_0^{\frac{3}{2}} + \left. {\left( {{x^2} - 3x} \right)} \right|_{\frac{3}{2}}^2 = \frac{9}{4} + \frac{1}{4} = \frac{5}{2}\]