Tính tích phân 8 landa 0 | x^2 - 6x | dx

Ta có:

 \[\begin{array}{l}\int\limits_0^8 {\left| {{x^2} - 6x} \right|{\rm{d}}x}  = \int\limits_0^6 {\left| {{x^2} - 6x} \right|{\rm{d}}x + \int\limits_6^8 {\left| {{x^2} - 6x} \right|{\rm{d}}x} }  = \int\limits_0^6 {\left( { - {x^2} + 6x} \right){\rm{d}}x + \int\limits_6^8 {\left( {{x^2} - 6x} \right){\rm{d}}x} } \\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left( {\frac{{ - {x^3}}}{3} + \frac{{6{x^2}}}{2}} \right)\left| {\begin{array}{*{20}{c}}{^6}\\{_0}\end{array}} \right. + \left( {\frac{{{x^3}}}{3} - \frac{{6{x^2}}}{2}} \right)\left| {\begin{array}{*{20}{c}}{^8}\\{_6}\end{array}} \right. = \frac{{152}}{3}\end{array}\]

Chọn đáp án A.