Tính tích phân (2024x + 2025 ) dx

Theo tính chất của tích phân, ta có:

 \[\begin{array}{l}\int\limits_0^1 {\left( {2024x + 2025} \right){\rm{d}}x}  = \int\limits_0^1 {2024x{\rm{d}}x + \int\limits_0^1 {2025} {\rm{d}}x} \\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left( {\frac{{2024{x^2}}}{2} + 2025x} \right)\left| {\begin{array}{*{20}{c}}{^1}\\{_0}\end{array}} \right. = \left( {\frac{{{{2024.1}^2}}}{2} + 2025.1} \right) - \left( {\frac{{{{2024.0}^2}}}{2} + 2025.0} \right)\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 3037\end{array}\]

Chọn đáp án C.