Tính lim x đến 0 căn 2x +4 + căn 3 của 5x+8 - căn 3x+1 -3/ x^2 +3x

Lờigiải

Ta có:

2x+4+5x+83−3x+1−3x2+3x

=2x+4−2+5x+83−2−3x+1−1x+3x

=2x2x+4+2x+3x+5x5x+832+25x+83+22x+3x−3x3x+1+1x+3x

=22x+4+2x+3+55x+832+25x+83+4x+3−33x+1+1x+3

Do đó limx→02x+4+5x+83−3x+1−3x2+3x

=limx→022x+4+2x+3+55x+832+25x+83+4x+3−33x+1+1x+3

=22+23+54+4+43−31+13

=16+536−12=−736.

Kết luận: limx→02x+4+5x+83−3x+1−3x2+3x=−736.