Tính I = lim ( căn n^2 -2n +3 -n )
Giải thích
Ta có I=limn2−2n+3−n =limn2−2n+3−nn2−2n+3+nn2−2n+3+n=limn2−2n+3−n2n2−2n+3+n
=lim−2n+3n2−2n+3+n=lim−2+3n1−2n+3n2+1=−21+1=−1.
Ta có I=limn2−2n+3−n =limn2−2n+3−nn2−2n+3+nn2−2n+3+n=limn2−2n+3−n2n2−2n+3+n
=lim−2n+3n2−2n+3+n=lim−2+3n1−2n+3n2+1=−21+1=−1.