Tính giới hạn lom (2n+1)^2 (3/(n^2 +2n) - 1/(n^2 +3n -1
Giải thích
lim2n+123n2+2n−1n2+3n−1=lim2n+122n2+7n−3n2+2nn2+3n−1=limn22+1n2.n22+7n−3n2n21+2n.n21+3n−1n2=lim2+1n22+7n−3n21+2n1+3n−1n2=22.21.1=8
Chọn đáp án D
lim2n+123n2+2n−1n2+3n−1=lim2n+122n2+7n−3n2+2nn2+3n−1=limn22+1n2.n22+7n−3n2n21+2n.n21+3n−1n2=lim2+1n22+7n−3n21+2n1+3n−1n2=22.21.1=8
Chọn đáp án D