Tính giới hạn lim (2-3n)^3 (n+1)^2 / 1-4n^5

Chọn D

\(\lim \frac{{{{\left( {2 - 3n} \right)}^3}{{\left( {n + 1} \right)}^2}}}{{1 - 4{n^5}}} = \lim \frac{{{n^3}{{\left( {\frac{2}{n} - 3} \right)}^3}{n^2}{{\left( {1 + \frac{1}{n}} \right)}^2}}}{{{n^5}\left( {\frac{1}{{{n^5}}} - 4} \right)}} = \lim \frac{{{{\left( {\frac{2}{n} - 3} \right)}^3}{{\left( {1 + \frac{1}{n}} \right)}^2}}}{{\frac{1}{{{n^5}}} - 4}} = \frac{{{{\left( {0 - 3} \right)}^3}{{\left( {1 + 0} \right)}^2}}}{{0 - 4}} = \frac{{27}}{4}\)