Tính giá trị của các biểu thức sau (tính hợp lí nếu có thể): (a) 2 /5 − 1 /5 . 3 /− 4
a) \(\frac{2}{5} - \frac{1}{5}.\frac{3}{{ - 4}} = \frac{2}{5} - \frac{3}{{ - 20}} = \frac{8}{{20}} + \frac{3}{{20}} = \frac{{11}}{{20}}\);
b) \(\frac{{{5^4}{{.20}^4}}}{{{{25}^5}{{.4}^5}}} = \frac{{{{\left( {5.20} \right)}^4}}}{{{{\left( {25.4} \right)}^5}}} = \frac{{{{100}^4}}}{{{{100}^5}}} = \frac{{{{100}^4}}}{{{{100}^4}.100}} = \frac{1}{{100}}\);
c) \[\sqrt {\frac{4}{9}} - \left| {\frac{{ - 3}}{7}} \right|.\frac{7}{8} = \frac{2}{3} - \frac{3}{7}.\frac{7}{8} = \frac{2}{3} - \frac{3}{8} = \frac{{16}}{{24}} - \frac{9}{{24}} = \frac{5}{{24}}\];
d) \(\left( {\frac{{ - 3}}{4} + \frac{4}{{15}}} \right):\frac{{2022}}{{2023}} + \left( {\frac{{ - 1}}{4} + \frac{{11}}{{15}}} \right):\frac{{2022}}{{2023}}\)
\( = \left( {\frac{{ - 3}}{4} + \frac{4}{{15}}} \right).\frac{{2023}}{{2022}} + \left( {\frac{{ - 1}}{4} + \frac{{11}}{{15}}} \right).\frac{{2023}}{{2022}}\)
\[ = \left( {\frac{{ - 3}}{4} + \frac{4}{{15}} + \frac{{ - 1}}{4} + \frac{{11}}{{15}}} \right).\frac{{2023}}{{2022}} = \left( { - 1 + 1} \right).\frac{{2023}}{{2022}} = 0\].