Tính đạo hàm các hàm số sau: a) y=(x^2-2/x+ 4 căn x)^3

a) y'=x2−2x+4x3'

=3x2−2x+4x2x2−2x+4x'

=3x2−2x+4x22x+2x2+2x

=6x2−2x+4x2x+1x2+1x

Vậy y'=6x2−2x+4x2x+1x2+1x

b) y' = [2^x + log₃(1 – 2x)]' = 2xln2+1−2x'1−2xln3=2xln2−21−2xln3

Vậy y'=2xln2−21−2xln3

c) y'=1−2xx2+1'=1−2x'x2+1−1−2xx2+1'x2+12

=−2x2+1−2x1−2xx2+12=−2x2−2−2x+4x2x2+12=2x2−2x−2x2+12

Vậy y'=2x2−2x−2x2+12

d) y' = (sin2x + cos²3x)' = cos2x×(2x)' + 2cos3x×(cos3x)'

= 2cos2x – 6cos3xsin3x = 2cos2x – 3sin6x.

Vậy y' = 2cos2x – 3sin6x.