Tính: căn 2 căn 3
Giải thích
\(\sqrt {\frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt 3 + \sqrt 2 }}} + \sqrt {\frac{{\sqrt 3 + \sqrt 2 }}{{\sqrt 3 - \sqrt 2 }}} \)=\(\sqrt {\frac{{{{\left( {\sqrt 3 - \sqrt 2 } \right)}^2}}}{{3 - 2}}} + \sqrt {\frac{{{{\left( {\sqrt 3 + \sqrt 2 } \right)}^2}}}{{3 - 2}}} \)
=\(\sqrt {{{\left( {\sqrt 3 - \sqrt 2 } \right)}^2}} + \sqrt {{{\left( {\sqrt 3 + \sqrt 2 } \right)}^2}} \)=\(\sqrt 3 - \sqrt 2 + \sqrt 3 + \sqrt 2 = 2\sqrt 3 \)