Đề cương ôn tập cuối kì 2 Toán lớp 4 (có đáp án) - Phần II. Tự luận

Tính biểu thức Tính a) 6/5 + 9/10

7/30

Tính

a) \(\frac{6}{5} + \frac{9}{{10}}\)             b) \(\frac{9}{{16}} - \frac{1}{4}\)              c) \(\frac{7}{{18}} \times \frac{9}{4}\)              d) \(\frac{8}{{15}}:\frac{7}{5}\)

e) \(\frac{4}{9} + \frac{7}{3}\)                  f) \(\frac{{11}}{{15}} - \frac{2}{5}\)             g) \(\frac{7}{{24}} \times \frac{{12}}{{49}}\)                          h) \(\frac{9}{{20}}:\frac{5}{4}\)

0/3000 ký tự
Giải thích

a) \(\frac{6}{5} + \frac{9}{{10}} = \frac{{12}}{{10}} + \frac{9}{{10}} = \frac{{21}}{{10}}\)     b) \(\frac{9}{{16}} - \frac{1}{4} = \frac{9}{{16}} - \frac{4}{{16}} = \frac{5}{{16}}\)

c) \(\frac{7}{{18}} \times \frac{9}{4} = \frac{7}{8}\)                                            d) \(\frac{8}{{15}}:\frac{7}{5} = \frac{8}{{15}} \times \frac{5}{7} = \frac{8}{{21}}\)

e) \(\frac{4}{9} + \frac{7}{3} = \frac{4}{9} + \frac{{21}}{9} = \frac{{25}}{9}\)     f) \(\frac{{11}}{{15}} - \frac{2}{5} = \frac{{11}}{{15}} - \frac{6}{{15}} = \frac{5}{{15}} = \frac{1}{3}\)

g) \[\frac{7}{{24}} \times \frac{{12}}{{49}} = \frac{{\cancel{7} \times \cancel{{12}}}}{{\cancel{{12}} \times 2 \times \cancel{7} \times 7}} = \frac{1}{{14}}\]     h) \(\frac{9}{{20}}:\frac{5}{4} = \frac{9}{{20}} \times \frac{4}{5} = \frac{9}{{25}}\)