Đề cương ôn tập cuối kì 2 Toán lớp 5 Cánh diều có đáp án - Phần II. Tự luận

Tính biểu thức Tính a) 2/5 + 1/6 + 7/30

4/30

Tính

a) \[\frac{2}{5} + \frac{1}{6} + \frac{7}{{30}}\]

c) \[\frac{{49}}{{24}} - \frac{2}{3} - \frac{5}{8}\]

b) \[\frac{1}{8} \times \frac{4}{5} + \frac{1}{8} \times \frac{9}{{10}} + \frac{1}{8} \times \frac{3}{2}\]

d) \[\frac{{2 \times 9 \times 5 \times 11}}{{33 \times 5 \times 4}}\]

0/3000 ký tự
Giải thích

a) \[\frac{2}{5} + \frac{1}{6} + \frac{7}{{30}}\]\[ = \frac{{12}}{{30}} + \frac{5}{{30}} + \frac{7}{{30}}\]\[ = \frac{{24}}{{30}} = \frac{4}{5}\]

b) \[\frac{1}{8} \times \frac{4}{5} + \frac{1}{8} \times \frac{9}{{10}} + \frac{1}{8} \times \frac{3}{2}\]

\[ = \frac{1}{8} \times \left( {\frac{4}{5} + \frac{9}{{10}} + \frac{3}{2}} \right)\]

\[ = \frac{1}{8} \times \left( {\frac{8}{{10}} + \frac{9}{{10}} + \frac{{15}}{{10}}} \right)\]

\[ = \frac{1}{8} \times \frac{{32}}{{10}}\]\[ = \frac{2}{5}\]

c) \[\frac{{49}}{{24}} - \frac{2}{3} - \frac{5}{8}\]\[ = \frac{{49}}{{24}} - \frac{{16}}{{24}} - \frac{{15}}{{24}}\]\[ = \frac{{18}}{{24}} = \frac{3}{4}\]

d) \[\frac{{2 \times 9 \times 5 \times 11}}{{33 \times 5 \times 4}}\]\[ = \frac{{\cancel{2} \times \cancel{3} \times 3 \times \cancel{5} \times \cancel{{11}}}}{{\cancel{3} \times \cancel{{11}} \times \cancel{5} \times \cancel{2} \times 2}}\]\[ = \frac{3}{2}\]