Đề thi cuối kì 1 Toán lớp 5 (có đáp án) - Đề 5

Tính bằng cách thuận tiện: a) 4/7 x 3 2/5 + 4/7 x 9 /10 - 4/7 x 7/2

Giải thích

a) \(\frac{4}{7} \times 3\frac{2}{5} + \frac{4}{7} \times \frac{9}{{10}} - \frac{4}{7} \times \frac{7}{2}\)

\( = \frac{4}{7} \times \left( {\frac{{17}}{5} + \frac{9}{{10}} - \frac{7}{2}} \right)\)

\( = \frac{4}{7} \times \left( {\frac{{17 \times 2 + 9 - 7 \times 5}}{{10}}} \right)\)

\( = \frac{4}{7} \times \frac{8}{{10}}\)

\( = \frac{{16}}{{35}}\)

b) \(\frac{3}{4} \times \frac{7}{6} - \frac{7}{4} \times \frac{1}{6} + \frac{2}{3} \times \frac{7}{4}\)

\( = \frac{7}{4} \times \frac{3}{6} - \frac{7}{4} \times \frac{1}{6} + \frac{2}{3} \times \frac{7}{4}\)

\( = \frac{7}{4} \times \left( {\frac{3}{6} - \frac{1}{6} + \frac{2}{3}} \right)\)

\( = \frac{7}{4} \times 1 = \frac{7}{4}\)