Tính: a) 8 log 2 5 b) 1/10 log 81 c) 5 log 25 16
Giải thích
a) 8log25=23log25=23log25=2log253=53=125;
b) 110log81=10−log81=10log81−1=81−1=181;
c) 5log2516=5log5216=512log516=5log51612=1612=16=4.
a) 8log25=23log25=23log25=2log253=53=125;
b) 110log81=10−log81=10log81−1=81−1=181;
c) 5log2516=5log5216=512log516=5log51612=1612=16=4.