Đề cương ôn tập cuối kì 2 Toán lớp 4 Cánh diều có đáp án - Phần II. Tự luận

Tính: a) 5 /6 + 3/2

7/30

Tính:

a) \[\frac{5}{6} + \frac{3}{2}\]                 b) \[\frac{9}{5} - \frac{3}{{10}}\]c) \[\frac{5}{9} \times \frac{2}{7}\]  d) \[\frac{6}{{11}}:\frac{7}{2}\]

e) \[\frac{8}{9} + \frac{2}{3}\]                 f) \[\frac{9}{4} - \frac{5}{6}\]      g) \[\frac{6}{7} \times \frac{8}{9}\]  h) \[\frac{4}{9}:\frac{5}{7}\]

0/3000 ký tự
Giải thích

a) \[\frac{5}{6} + \frac{3}{2} = \frac{5}{6} + \frac{9}{6} = \frac{{14}}{6} = \frac{7}{3}\]  b) \[\frac{9}{5} - \frac{3}{{10}} = \frac{{18}}{{10}} - \frac{3}{{10}} = \frac{{16}}{{10}} = \frac{8}{5}\]

c) \[\frac{5}{9} \times \frac{2}{7} = \frac{{10}}{{63}}\]             d) \[\frac{6}{{11}}:\frac{7}{2} = \frac{6}{{11}} \times \frac{2}{7} = \frac{{12}}{{77}}\]

e) \[\frac{8}{9} + \frac{2}{3} = \frac{8}{9} + \frac{6}{9} = \frac{{14}}{9}\]       f) \[\frac{9}{4} - \frac{5}{6} = \frac{{27}}{{12}} - \frac{{10}}{{12}} = \frac{{17}}{{12}}\]

g) \[\frac{6}{7} \times \frac{8}{9} = \frac{{48}}{{63}} = \frac{{16}}{{21}}\]           h) \[\frac{4}{9}:\frac{5}{7} = \frac{4}{9} \times \frac{7}{5} = \frac{{28}}{{45}}\]