Tính 4cos15 độ.cos24 độ.cos21 độ - cos12 độ - cos18 độ. 1/2 + căn 3/2
Giải thích
Đáp án A
4cos150cos240cos210−cos120−cos180=2cos150cos240+210+cos240−210−2cos120+1802cos120−1802=2cos150cos450+cos30−2cos150cos30=2cos150.cos450=cos600+cos300=12+32
Đáp án A
4cos150cos240cos210−cos120−cos180=2cos150cos240+210+cos240−210−2cos120+1802cos120−1802=2cos150cos450+cos30−2cos150cos30=2cos150.cos450=cos600+cos300=12+32