Tính: (2^23 2^24 2^25):(2^18 2^19 2^20)

Lời giải:

\[\frac{{{2^{23}} + {\rm{ }}{2^{24}} + {\rm{ }}{2^{25}}}}{{{2^{18}} + {2^{19}} + {2^{20}}}}\]

\[ = \frac{{{2^{18}}\left( {{2^5} + {\rm{ }}{2^6} + {\rm{ }}{2^7}} \right)}}{{{2^{18}}\left( {{2^0} + {2^1} + {2^2}} \right)}}\]

\[ = \frac{{{2^5}\left( {{2^0} + {\rm{ }}{2^1} + {\rm{ }}{2^2}} \right)}}{{{2^0} + {2^1} + {2^2}}}\]

= 2⁵ = 32.