Tìm x biết (2x - 3)^2 - (4x - 6)(x + 2) = x^2 + 4x + 4 = 0
Giải thích
Ta có: 2x−32−4x−6x+2+x2+4x+4=0
⇔2x−32−22x−3x+2+x+22=0
⇔3x−2−x+22=0⇔3x−2−x−22=0
⇔2x−42=0⇔2x−4=0⇔x=2
Ta có: 2x−32−4x−6x+2+x2+4x+4=0
⇔2x−32−22x−3x+2+x+22=0
⇔3x−2−x+22=0⇔3x−2−x−22=0
⇔2x−42=0⇔2x−4=0⇔x=2