Tìm x ∈ Z , biết rằng: j) 5 ⋅ 1/ 6 + 1/ 6 ≤ x ≤ 1/ 4 : 1 /13 + 7/ 4
Giải thích
j) \(5 \cdot \frac{1}{6} + \frac{1}{6} \le x \le \frac{1}{4}:\frac{1}{{13}} + \frac{7}{4}\)
\[\left( {5 + 1} \right) \cdot \frac{1}{6} \le x \le \frac{1}{4} \cdot \frac{{13}}{1} + \frac{7}{4}\]
\[\frac{1}{6} \cdot 6 \le x \le \frac{{13}}{4} + \frac{7}{4}\]
\[1 \le x \le \frac{{20}}{4}\]
\[1 \le x \le 5\]
Vì \[x \in \mathbb{Z}\] nên \[x \in \left\{ {1;\,\,2;\,\,3;\,\,4;\,\,5} \right\}\].
Vậy \[x \in \left\{ {1;\,\,2;\,\,3;\,\,4;\,\,5} \right\}\].