Tìm x ,y , z thuộc Q biết:|x+1/2|+|y-3/4|+|z-1|=0
Giải thích
x+12+y−34+z−1=0 mà x+12≥0;y−34≥0;z−1≥0
⇒x+12=0y−34=0z−1=0⇒x+12=0y−34=0z−1=0⇒x=−12y=34z=1
Vậy x=−12; y=34; z=1
x+12+y−34+z−1=0 mà x+12≥0;y−34≥0;z−1≥0
⇒x+12=0y−34=0z−1=0⇒x+12=0y−34=0z−1=0⇒x=−12y=34z=1
Vậy x=−12; y=34; z=1