Tìm x: x/2 - 1/x = 1/12
Giải thích
x2−1x=112x2−22x=11212x2−2=2x 6x2−2=x6x2−x−12=06x2+8x−9x−12=02x3x+4−33x+4=03x+42x−3=0
TH1: 3x + 4 = 0
3x=−4 x=−43
TH2: 2x - 3 = 0
2x=3 x=32Vậy x∈−43; 32
x2−1x=112x2−22x=11212x2−2=2x 6x2−2=x6x2−x−12=06x2+8x−9x−12=02x3x+4−33x+4=03x+42x−3=0
TH1: 3x + 4 = 0
3x=−4 x=−43
TH2: 2x - 3 = 0
2x=3 x=32Vậy x∈−43; 32