Tìm x h) ( x − 5 ) mũ 2 022 = ( x − 5 ) mũ 2 021 .

h) \[{\left( {x - 5} \right)^{2\,022}} = {\left( {x - 5} \right)^{2\,021}}\]

\[{\left( {x - 5} \right)^{2\,021}} \cdot \left( {x - 5} \right) - {\left( {x - 5} \right)^{2\,021}} = 0\]

\[{\left( {x - 5} \right)^{2\,021}} \cdot \left( {x - 5 - 1} \right) = 0\]

\[{\left( {x - 5} \right)^{2\,021}} \cdot \left( {x - 6} \right) = 0\]

Suy ra \[{\left( {x - 5} \right)^{2\,021}} = 0\] hoặc \[x - 6 = 0\]

\[x - 5 = 0\] hoặc \[x = 6\]