Tìm x của biểu thức, biết: a) 1/5 − x = − 3/4 ; b) ( x − 215 )^3 = 8 /125 ;
a) \(\frac{1}{5} - x = \frac{{ - 3}}{4}\) \(x = \frac{1}{5} + \frac{3}{4}\) \(x = \frac{{19}}{{20}}\) Vậy \(x = \frac{{19}}{{20}}\). | b) \({\left( {x - \frac{2}{{15}}} \right)^3} = \frac{8}{{125}}\) \({\left( {x - \frac{2}{{15}}} \right)^3} = {\left( {\frac{2}{5}} \right)^3}\) Suy ra \(x - \frac{2}{{15}} = \frac{2}{5}\) \(x = \frac{2}{5} + \frac{2}{{15}}\) \(x = \frac{8}{{15}}\) Vậy \(x = \frac{8}{{15}}\). | c) \(\left| {\frac{8}{3} - 3x} \right| - \frac{2}{3} = \frac{1}{2}\) \(\left| {\frac{8}{3} - 3x} \right| = \frac{1}{2} + \frac{2}{3}\) \(\left| {\frac{8}{3} - 3x} \right| = \frac{7}{6}\) | |
Trường hợp 1: \(\frac{8}{3} - 3x = \frac{7}{6}\) \(3x = \frac{8}{3} - \frac{7}{6}\) \(3x = \frac{9}{6} = \frac{3}{2}\) \(x = \frac{3}{2}:3\) \(x = \frac{1}{2}\) Vậy \(x \in \left\{ {\frac{1}{2};\frac{{23}}{{18}}} \right\}\). | Trường hợp 2: \(\frac{8}{3} - 3x = - \frac{7}{6}\) \(3x = \frac{8}{3} + \frac{7}{6}\) \(3x = \frac{{23}}{6}\) \(x = \frac{{23}}{6}:3\) \(x = \frac{{23}}{{18}}\)
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