Tìm x biết: x - 2/9 ^3 = 2/3 ^6

\({\left( {x - \frac{2}{9}} \right)^3} = {\left( {\frac{2}{3}} \right)^6}\)

\({\left( {x - \frac{2}{9}} \right)^3} = {\left[ {{{\left( {\frac{2}{3}} \right)}^2}} \right]^3}\)

⇒ \(x - \frac{2}{9} = {\left( {\frac{2}{3}} \right)^2}\)

⇔ \(x - \frac{2}{9} = \frac{4}{9}\)

⇔ \(x = \frac{2}{9} + \frac{4}{9}\)

⇔ \(x = \frac{6}{9} = \frac{2}{3}\)

Vậy \(x = \frac{2}{3}\)