Tìm x biết: |x + 1| = |3 – 2x|

|x + 1| = |3 – 2x|

⇒ \(\left[ \begin{array}{l}x + 1 = 3 - 2x\\x + 1 = - \left( {3 - 2x} \right)\end{array} \right.\)

⇔ \(\left[ \begin{array}{l}x + 1 = 3 - 2x\\x + 1 = - \left( {3 - 2x} \right)\end{array} \right.\)

⇔ \(\left[ \begin{array}{l}3x = 2\\ - x = - 4\end{array} \right.\)

⇔ \(\left[ \begin{array}{l}x = \frac{2}{3}\\x = 4\end{array} \right.\)