Tìm (x), biết:

a) \({2^x}:4 = 16\)

\({2^x} = 64\)

\({2^x} = {2^6}\)

Suy ra \(x = 6\).

Vậy \(x = 6\).

b) \[ - 3x + 25 =  - 2\]

\[ - 3x =  - 27\]

\(x = 9\)

Vậy \(x = 9\).

c) \(37 - 2\left( {x + 6} \right) = 29\)

\(2\left( {x + 6} \right) = 8\)

\(x + 6 = 4\)

\(x =  - 2\)

Vậy \(x =  - 2\).

d) \({\left( {4x - 11} \right)^6} = {25^3}\)

\({\left( {4x - 11} \right)^6} = {\left( {{5^2}} \right)^3}\)

\({\left( {4x - 11} \right)^6} = {5^6} = {\left( { - 5} \right)^6}\)

Trường hợp 1:

\(4x - 11 = 5\)

\(4x = 16\)

\(x = 4\)

Vậy \(x \in \left\{ {4;1,5} \right\}\).

Trường hợp 2:

\(4x - 11 =  - 5\)

\(4x = 6\)

\(x = 1,5\)