Tìm \(x\), biết: \(\frac{{x + 2}}{3} - \frac{3}{4} = \frac{5}{3} + \frac{1}{{15}}\).
Giải thích
Hướng dẫn giải
Đáp án: \(x = \frac{{109}}{{20}}\)
Ta có: \(\frac{{x + 2}}{3} - \frac{3}{4} = \frac{5}{3} + \frac{1}{{15}}\)
\(\frac{x}{3} + \frac{2}{3} - \frac{3}{4} = \frac{{26}}{{15}}\)
\(\frac{x}{3} = \frac{{26}}{{15}} + \frac{3}{4} - \frac{2}{3}\)
\(\frac{x}{3} = \frac{{109}}{{60}}\)
\(x = \frac{{109}}{{60}}.3\)
\(x = \frac{{109}}{{20}}\).
Vậy \(x = \frac{{109}}{{20}}\).