Tìm \(x\), biết: \(\frac{{2x}}{3} + \frac{{3x - 1}}{6} = \frac{x}{2}\).

Đáp án: \(x = \frac{3}{4}\)

Ta có: \(\frac{{2x}}{3} + \frac{{3x - 1}}{6} = \frac{x}{2}\)

\(\frac{{2x}}{3} + \frac{{3x}}{6} - \frac{1}{6} = \frac{x}{2}\)

\(\frac{{2x}}{3} + \frac{{3x}}{6} - \frac{x}{2} = \frac{1}{2}\)

\(\frac{{4x}}{6} + \frac{{3x}}{6} - \frac{{3x}}{6} = \frac{1}{2}\)

\(\frac{{4x}}{6} = \frac{1}{2}\)

\(4x = 3\)

\(x = \frac{3}{4}\).

Vậy \(x = \frac{3}{4}\).