Tìm x biết f) 125 − 3 ( x + 3 ) = 65 .
Giải thích
f) \(125 - 3\left( {x + 3} \right) = 65\)
\(3\left( {x + 3} \right) = 125 - 65\)
\(3\left( {x + 3} \right) = 60\)
\(x + 3 = 60:3\)
\(x + 3 = 20\)
\(x = 20 - 3\)
\(x = 17\).
Vậy \(x = 17\).
f) \(125 - 3\left( {x + 3} \right) = 65\)
\(3\left( {x + 3} \right) = 125 - 65\)
\(3\left( {x + 3} \right) = 60\)
\(x + 3 = 60:3\)
\(x + 3 = 20\)
\(x = 20 - 3\)
\(x = 17\).
Vậy \(x = 17\).