Tìm x , biết: e) x ^2 − 4 − ( x − 2 ) = 0 .

e) \({x^2} - 4 - \left( {x - 2} \right) = 0\)

\(\left( {x - 2} \right)\left( {x + 2} \right) - \left( {x - 2} \right) = 0\)

\(\left( {x - 2} \right)\left( {x + 2 - 1} \right) = 0\)

\[\left( {x - 2} \right)\left( {x + 1} \right) = 0\]

\(x - 2 = 0\) hoặc \(x + 1 = 0\)

\(x = 2\) hoặc \(x = - 1\).

Vậy \(x = 2\); \(x = - 1\).