Tìm x biết: a) x - 5/6 = 1/9

a) \(x - \frac{5}{6} = \frac{1}{9}\)

\(x = \frac{1}{9} + \frac{5}{6}\)

\(x = \frac{2}{{18}} + \frac{{15}}{{18}} = \frac{{17}}{{18}}.\)

Vậy \(x = \frac{{17}}{{18}}.\)

b) \(\frac{1}{3} + \frac{2}{3} \cdot x = {2024^0}\)

\(\frac{2}{3} \cdot x = 1 - \frac{1}{3}\)

\(\frac{2}{3} \cdot x = \frac{2}{3}\)

\(x = 1.\)

Vậy \(x = 1.\)